Web Reference: The lambda calculus executes via a substitution model. When you apply arguments to a function, you instantiate the function body, replacing its parameters with the actual arguments that were passed in (like we were doing above). You have to be careful when doing this to avoid name collisions. But in the lambda calculus, names don't really matter. Lambda calculus seems to strike a balance where parameters are labelled but arguments are not. Automata like Turing machines are notoriously hard to write programs in, and tape-based machines don't compose very well since tapes aren't structurally inductive. I think the second key difference is that the lambda calculus is easy to modify and ... Lambda-Calculus-Reduction So im having an exam quite soon and i have to be able to do Lambda-Calc. I have some problems with getting consisten right answers. An example: We got this: (λab.b (λa.a)ab)a (λba.ab) First task is to rename all variables so we do not have any variables with the same name via alpha-conversion. i came to this:
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